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US Army Corps of EngineersInstitute for Water Resources, Risk Management Center

Appendix B - Summary of Hydraulic Shear Stress Equations

Table: Hydraulic shear stress in pipe or crack.
Transverse FlawTailwater above Base of Pipe/Crack (H2>0)(H_{2}>0)Tailwater below Base of Pipe/Crack (H2=0)(H_{2}=0)Approximation for No Tailwater and Small Flaw
Cylindrical Pipeτ=γw(H1H2L)D4=γwiD4\tau = \gamma_{w}\left(\frac{H_{1}-H_{2}}{L}\right)\frac{D}{4} = \frac{\gamma_{w}iD}{4}τ=γw(H1H2L)D4=γwiD4\tau = \gamma_{w}\left(\frac{H_{1}-H_{2}}{L}\right)\frac{D}{4} = \frac{\gamma_{w}iD}{4} τ=γw(H1H2L)D4=γwiD4\tau = \gamma_{w}\left(\frac{H_{1}-H_{2}}{L}\right)\frac{D}{4} = \frac{\gamma_{w}iD}{4}
Horizontal Crack τ=γw(H1H2L)WX2W+2X=γwiWX(2W+2X)\tau = \gamma_{w}\left(\frac{H_{1}-H_{2}}{L}\right) \frac{WX}{2W+2X} = \frac{\gamma_{w}iWX}{(2W+2X)} τ=γw(H1H2L)WX2W+2X=γwiWX(2W+2X)\tau = \gamma_{w}\left(\frac{H_{1}-H_{2}}{L}\right) \frac{WX}{2W+2X} = \frac{\gamma_{w}iWX}{(2W+2X)}τγwiW2,W<<X\tau \approx \frac{\gamma_{w}iW}{2}, W<<X
Vertical Rectangular Crack τ=γwW(H12H22)2L(H1+H2+W)\tau = \frac{\gamma_{w}W(H_{1}^{2}-H_{2}^2)}{2L(H_{1}+H_{2}+W)} τ=γwH12W2(H1+W)L\tau = \frac{\gamma_{w}H_{1}^{2}W}{2(H_{1}+W)L} τγwWH12L=γwiW2,W<<H1\tau \approx \frac{\gamma_{w}WH_{1}}{2L} = \frac{\gamma_{w}iW}{2}, W<<H_{1}
Vertical Triangular Crack τ=γwW6DL(H13H23)(H1+H2)1+W24D2\tau = \frac{\gamma_{w}W}{6DL}\frac{(H_{1}^{3}-H_{2}^3)}{(H_{1}+H_2)\sqrt{1+\frac{W^2}{4D^2}}} τ=γwW6DL(H12)1+W24D2\tau = \frac{\gamma_{w}W}{6DL}\frac{(H_{1}^{2})}{\sqrt{1+\frac{W^2}{4D^2}}} τγwWH126DL=γwiWH16D,W<<D\tau \approx \frac{\gamma_{w}WH_{1}^{2}}{6DL} = \frac{\gamma_{w}iWH_{1}}{6D}, W<<D
Table: Critical pipe diameter or crack width.
Transverse FlawTailwater above Base of Pipe/Crack (H2>0)(H_{2}>0)Tailwater below Base of Pipe/Crack (H2=0)(H_{2}=0)Approximation for No Tailwater and Small W
Cylindrical PipeDcr=4τcγwiD_{cr} = \frac{4\tau_{c}}{\gamma_{w}i}Dcr=4τcγwiD_{cr} = \frac{4\tau_c}{\gamma_{w}i} Dcr=4τcγwiD_{cr} = \frac{4\tau_c}{\gamma_{w}i}
Horizontal Crack Wcr=2LτcX2Lτcγw(H1H2)XW_{cr} = \frac{-2L\tau_{c}X}{2L\tau_{c}-\gamma_{w}(H_{1}-H_{2})X} Wcr=2LτcX2LτcγwH1XW_{cr} = \frac{-2L\tau_{c}X}{2L\tau_{c}-\gamma_{w}H_{1}X}Wcr2τcγwi,W<<XW_{cr} \approx \frac{2\tau_c}{\gamma_{w}i}, W<<X
Vertical Rectangular Crack Wcr=2Lτc(H1+H2)γw(H12H22)2LτcW_{cr} = \frac{2L\tau_{c}(H_{1}+H_2)}{\gamma_{w}(H_{1}^{2}-H_{2}^{2})-2L\tau_c} Wcr=2LτcH1γwH122LτcW_{cr} = \frac{2L\tau_{c}H_{1}}{\gamma_{w}H_{1}^{2}-2L\tau_c} Wcr2τcγwi,W<<H1W_{cr} \approx \frac{2\tau_c}{\gamma_{w}i}, W<<H_{1}
Vertical Triangular Crack Wcr=τc(H1+H2)γw2(H13H23)236D2L2τc2(H1+H2)24D2W_{cr} = \frac{\tau_{c}(H_{1}+H_{2})}{\sqrt{\frac{\gamma_{w}^{2}(H_{1}^{3} - H_{2}^3)^2}{36D^{2}L^2} - \frac{\tau_{c}^{2}(H_{1}+H_{2})^2}{4D^2}}} Wcr=τcH1γw2H1636D2L2τc2H124D2W_{cr} = \frac{\tau_{c}H_1}{\sqrt{\frac{\gamma_{w}^{2}H_{1}^6}{36D^{2}L^2} - \frac{\tau_{c}^{2}H_{1}^2}{4D^2}}} Wcr6DτcγwiH1,W<<DW_{cr} \approx \frac{6D\tau_c}{\gamma_{w}iH_1}, W<<D